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charAt
public char charAt(
int index
)
Returns the character at the specified index. An index ranges
from 0 to length() - 1. The first character
of the sequence is at index 0, the next at index
1, and so on, as for array indexing.
compareTo
public int compareTo(
Object o
)
Compares this String to another Object. If the Object is a String,
this function behaves like compareTo(String). Otherwise,
it throws a ClassCastException (as Strings are comparable
only to other Strings).
compareTo
public int compareTo(
String anotherString
)
Compares two strings lexicographically.
The comparison is based on the Unicode value of each character in
the strings. The character sequence represented by this
String object is compared lexicographically to the
character sequence represented by the argument string. The result is
a negative integer if this String object
lexicographically precedes the argument string. The result is a
positive integer if this String object lexicographically
follows the argument string. The result is zero if the strings
are equal; compareTo returns 0 exactly when
the equals(Object) method would return true.
This is the definition of lexicographic ordering. If two strings are
different, then either they have different characters at some index
that is a valid index for both strings, or their lengths are different,
or both. If they have different characters at one or more index
positions, let k be the smallest such index; then the string
whose character at position k has the smaller value, as
determined by using the < operator, lexicographically precedes the
other string. In this case, compareTo returns the
difference of the two character values at position k in
the two string -- that is, the value:
this.charAt(k)-anotherString.charAt(k)
If there is no index position at which they differ, then the shorter
string lexicographically precedes the longer string. In this case,
compareTo returns the difference of the lengths of the
strings -- that is, the value:
this.length()-anotherString.length()
compareToIgnoreCase
public int compareToIgnoreCase(
String str
)
Compares two strings lexicographically, ignoring case
differences. This method returns an integer whose sign is that of
calling compareTo with normalized versions of the strings
where case differences have been eliminated by calling
Character.toLowerCase(Character.toUpperCase(character)) on
each character.
Note that this method does not take locale into account,
and will result in an unsatisfactory ordering for certain locales.
The java.text package provides collators to allow
locale-sensitive ordering.
concat
public String concat(
String str
)
Concatenates the specified string to the end of this string.
If the length of the argument string is 0, then this
String object is returned. Otherwise, a new
String object is created, representing a character
sequence that is the concatenation of the character sequence
represented by this String object and the character
sequence represented by the argument string.
Examples:
"cares".concat("s") returns "caress"
"to".concat("get").concat("her") returns "together"
contentEquals
public boolean contentEquals(
StringBuffer sb
)
Returns true if and only if this String represents
the same sequence of characters as the specified StringBuffer.
endsWith
public boolean endsWith(
String suffix
)
Tests if this string ends with the specified suffix.
equals
public boolean equals(
Object anObject
)
Compares this string to the specified object.
The result is true if and only if the argument is not
null and is a String object that represents
the same sequence of characters as this object.
equalsIgnoreCase
public boolean equalsIgnoreCase(
String anotherString
)
Compares this String to another String,
ignoring case considerations. Two strings are considered equal
ignoring case if they are of the same length, and corresponding
characters in the two strings are equal ignoring case.
Two characters c1 and c2 are considered
the same, ignoring case if at least one of the following is true:
- The two characters are the same (as compared by the
== operator).
- Applying the method toUpperCase(char)
to each character produces the same result.
- Applying the method toLowerCase(char)
to each character produces the same result.
getBytes
public byte[] getBytes(
)
Encodes this String into a sequence of bytes using the
platform's default charset, storing the result into a new byte array.
The behavior of this method when this string cannot be encoded in
the default charset is unspecified. The java.nio.charset.CharsetEncoder class should be used when more control
over the encoding process is required.
getBytes
public void getBytes(
int srcBegin,
int srcEnd,
byte[] dst,
int dstBegin
)
Copies characters from this string into the destination byte
array. Each byte receives the 8 low-order bits of the
corresponding character. The eight high-order bits of each character
are not copied and do not participate in the transfer in any way.
The first character to be copied is at index srcBegin;
the last character to be copied is at index srcEnd-1.
The total number of characters to be copied is
srcEnd-srcBegin. The characters, converted to bytes,
are copied into the subarray of dst starting at index
dstBegin and ending at index:
dstbegin + (srcEnd-srcBegin) - 1
getBytes
public byte[] getBytes(
String charsetName
)
throws
UnsupportedEncodingException
Encodes this String into a sequence of bytes using the
named charset, storing the result into a new byte array.
The behavior of this method when this string cannot be encoded in
the given charset is unspecified. The java.nio.charset.CharsetEncoder class should be used when more control
over the encoding process is required.
getChars
public void getChars(
int srcBegin,
int srcEnd,
char[] dst,
int dstBegin
)
Copies characters from this string into the destination character
array.
The first character to be copied is at index srcBegin;
the last character to be copied is at index srcEnd-1
(thus the total number of characters to be copied is
srcEnd-srcBegin). The characters are copied into the
subarray of dst starting at index dstBegin
and ending at index:
dstbegin + (srcEnd-srcBegin) - 1
hashCode
public int hashCode(
)
Returns a hash code for this string. The hash code for a
String object is computed as
s[0]*31^(n-1) + s[1]*31^(n-2) + ... + s[n-1]
using int arithmetic, where s[i] is the
ith character of the string, n is the length of
the string, and ^ indicates exponentiation.
(The hash value of the empty string is zero.)
indexOf
public int indexOf(
int ch
)
Returns the index within this string of the first occurrence of the
specified character. If a character with value ch occurs
in the character sequence represented by this String
object, then the index of the first such occurrence is returned --
that is, the smallest value k such that:
this.charAt(k) == ch
is true. If no such character occurs in this string,
then -1 is returned.
indexOf
public int indexOf(
int ch,
int fromIndex
)
Returns the index within this string of the first occurrence of the
specified character, starting the search at the specified index.
If a character with value ch occurs in the character
sequence represented by this String object at an index
no smaller than fromIndex, then the index of the first
such occurrence is returned--that is, the smallest value k
such that:
(this.charAt(k) == ch) && (k >= fromIndex)
is true. If no such character occurs in this string at or after
position fromIndex, then -1 is returned.
There is no restriction on the value of fromIndex. If it
is negative, it has the same effect as if it were zero: this entire
string may be searched. If it is greater than the length of this
string, it has the same effect as if it were equal to the length of
this string: -1 is returned.
indexOf
public int indexOf(
String str
)
Returns the index within this string of the first occurrence of the
specified substring. The integer returned is the smallest value
k such that:
this.startsWith(str, k)
is true.
indexOf
public int indexOf(
String str,
int fromIndex
)
Returns the index within this string of the first occurrence of the
specified substring, starting at the specified index. The integer
returned is the smallest value k for which:
k >= Math.min(fromIndex, str.length()) && this.startsWith(str, k)
If no such value of k exists, then -1 is returned.
intern
public native String intern(
)
Returns a canonical representation for the string object.
A pool of strings, initially empty, is maintained privately by the
class String.
When the intern method is invoked, if the pool already contains a
string equal to this String object as determined by
the equals(Object) method, then the string from the pool is
returned. Otherwise, this String object is added to the
pool and a reference to this String object is returned.
It follows that for any two strings s and t,
s.intern() == t.intern() is true
if and only if s.equals(t) is true.
All literal strings and string-valued constant expressions are
interned. String literals are defined in §3.10.5 of the
Java Language
Specification
lastIndexOf
public int lastIndexOf(
int ch
)
Returns the index within this string of the last occurrence of the
specified character. That is, the index returned is the largest
value k such that:
this.charAt(k) == ch
is true.
The String is searched backwards starting at the last character.
lastIndexOf
public int lastIndexOf(
int ch,
int fromIndex
)
Returns the index within this string of the last occurrence of the
specified character, searching backward starting at the specified
index. That is, the index returned is the largest value k
such that:
this.charAt(k) == ch) && (k <= fromIndex)
is true.
lastIndexOf
public int lastIndexOf(
String str
)
Returns the index within this string of the rightmost occurrence
of the specified substring. The rightmost empty string "" is
considered to occur at the index value this.length().
The returned index is the largest value k such that
this.startsWith(str, k)
is true.
lastIndexOf
public int lastIndexOf(
String str,
int fromIndex
)
Returns the index within this string of the last occurrence of the
specified substring, searching backward starting at the specified index.
The integer returned is the largest value k such that:
k <= Math.min(fromIndex, str.length()) && this.startsWith(str, k)
If no such value of k exists, then -1 is returned.
length
public int length(
)
Returns the length of this string.
The length is equal to the number of 16-bit
Unicode characters in the string.
matches
public boolean matches(
String regex
)
Tells whether or not this string matches the given regular expression.
An invocation of this method of the form
str.matches(regex) yields exactly the
same result as the expression
java.util.regex.Pattern.matches(regex, str)
regionMatches
public boolean regionMatches(
boolean ignoreCase,
int toffset,
String other,
int ooffset,
int len
)
Tests if two string regions are equal.
A substring of this String object is compared to a substring
of the argument other. The result is true if these
substrings represent character sequences that are the same, ignoring
case if and only if ignoreCase is true. The substring of
this String object to be compared begins at index
toffset and has length len. The substring of
other to be compared begins at index ooffset and
has length len. The result is false if and only if
at least one of the following is true:
- toffset is negative.
- ooffset is negative.
- toffset+len is greater than the length of this
String object.
- ooffset+len is greater than the length of the other
argument.
- ignoreCase is false and there is some nonnegative
integer k less than len such that:
this.charAt(toffset+k) != other.charAt(ooffset+k)
- ignoreCase is true and there is some nonnegative
integer k less than len such that:
Character.toLowerCase(this.charAt(toffset+k)) !=
Character.toLowerCase(other.charAt(ooffset+k))
and:
Character.toUpperCase(this.charAt(toffset+k)) !=
Character.toUpperCase(other.charAt(ooffset+k))
regionMatches
public boolean regionMatches(
int toffset,
String other,
int ooffset,
int len
)
Tests if two string regions are equal.
A substring of this String object is compared to a substring
of the argument other. The result is true if these substrings
represent identical character sequences. The substring of this
String object to be compared begins at index toffset
and has length len. The substring of other to be compared
begins at index ooffset and has length len. The
result is false if and only if at least one of the following
is true:
- toffset is negative.
- ooffset is negative.
- toffset+len is greater than the length of this
String object.
- ooffset+len is greater than the length of the other
argument.
- There is some nonnegative integer k less than len
such that:
this.charAt(toffset+k) != other.charAt(ooffset+k)
replace
public String replace(
char oldChar,
char newChar
)
Returns a new string resulting from replacing all occurrences of
oldChar in this string with newChar.
If the character oldChar does not occur in the
character sequence represented by this String object,
then a reference to this String object is returned.
Otherwise, a new String object is created that
represents a character sequence identical to the character sequence
represented by this String object, except that every
occurrence of oldChar is replaced by an occurrence
of newChar.
Examples:
"mesquite in your cellar".replace('e', 'o')
returns "mosquito in your collar"
"the war of baronets".replace('r', 'y')
returns "the way of bayonets"
"sparring with a purple porpoise".replace('p', 't')
returns "starring with a turtle tortoise"
"JonL".replace('q', 'x') returns "JonL" (no change)
replaceAll
public String replaceAll(
String regex,
String replacement
)
Replaces each substring of this string that matches the given regular expression with the
given replacement.
An invocation of this method of the form
str.replaceAll(regex, repl)
yields exactly the same result as the expression
java.util.regex.Pattern.compile(regex).matcher(str).replaceAll(repl)
replaceFirst
public String replaceFirst(
String regex,
String replacement
)
Replaces the first substring of this string that matches the given regular expression with the
given replacement.
An invocation of this method of the form
str.replaceFirst(regex, repl)
yields exactly the same result as the expression
java.util.regex.Pattern.compile(regex).matcher(str).replaceFirst(repl)
split
public String[] split(
String regex
)
Splits this string around matches of the given regular expression.
This method works as if by invoking the two-argument split method with the given expression and a limit
argument of zero. Trailing empty strings are therefore not included in
the resulting array.
The string "boo:and:foo", for example, yields the following
results with these expressions:
| Regex |
Result |
| : |
{ "boo", "and", "foo" } |
| o |
{ "b", "", ":and:f" } |
split
public String[] split(
String regex,
int limit
)
Splits this string around matches of the given regular expression.
The array returned by this method contains each substring of this
string that is terminated by another substring that matches the given
expression or is terminated by the end of the string. The substrings in
the array are in the order in which they occur in this string. If the
expression does not match any part of the input then the resulting array
has just one element, namely this string.
The limit parameter controls the number of times the
pattern is applied and therefore affects the length of the resulting
array. If the limit n is greater than zero then the pattern
will be applied at most n - 1 times, the array's
length will be no greater than n, and the array's last entry
will contain all input beyond the last matched delimiter. If n
is non-positive then the pattern will be applied as many times as
possible and the array can have any length. If n is zero then
the pattern will be applied as many times as possible, the array can
have any length, and trailing empty strings will be discarded.
The string "boo:and:foo", for example, yields the
following results with these parameters:
| Regex |
Limit |
Result |
| : |
2 |
{ "boo", "and:foo" } |
| : |
5 |
{ "boo", "and", "foo" } |
| : |
-2 |
{ "boo", "and", "foo" } |
| o |
5 |
{ "b", "", ":and:f", "", "" } |
| o |
-2 |
{ "b", "", ":and:f", "", "" } |
| o |
0 |
{ "b", "", ":and:f" } |
An invocation of this method of the form
str.split(regex, n)
yields the same result as the expression
java.util.regex.Pattern.compile(regex).split(str, n)
startsWith
public boolean startsWith(
String prefix
)
Tests if this string starts with the specified prefix.
startsWith
public boolean startsWith(
String prefix,
int toffset
)
Tests if this string starts with the specified prefix beginning
a specified index.
subSequence
public CharSequence subSequence(
int beginIndex,
int endIndex
)
Returns a new character sequence that is a subsequence of this sequence.
An invocation of this method of the form
str.subSequence(begin, end)
behaves in exactly the same way as the invocation
str.substring(begin, end)
This method is defined so that the String class can implement
the CharSequence interface.
substring
public String substring(
int beginIndex
)
Returns a new string that is a substring of this string. The
substring begins with the character at the specified index and
extends to the end of this string.
Examples:
"unhappy".substring(2) returns "happy"
"Harbison".substring(3) returns "bison"
"emptiness".substring(9) returns "" (an empty string)
substring
public String substring(
int beginIndex,
int endIndex
)
Returns a new string that is a substring of this string. The
substring begins at the specified beginIndex and
extends to the character at index endIndex - 1.
Thus the length of the substring is endIndex-beginIndex.
Examples:
"hamburger".substring(4, 8) returns "urge"
"smiles".substring(1, 5) returns "mile"
toCharArray
public char[] toCharArray(
)
Converts this string to a new character array.
toLowerCase
public String toLowerCase(
)
Converts all of the characters in this String to lower
case using the rules of the default locale. This is equivalent to calling
toLowerCase(Locale.getDefault()).
toLowerCase
public String toLowerCase(
Locale locale
)
Converts all of the characters in this String to lower
case using the rules of the given Locale. Case mappings rely
heavily on the Unicode specification's character data. Since case
mappings are not always 1:1 char mappings, the resulting String
may be a different length than the original String.
Examples of lowercase mappings are in the following table:
| Language Code of Locale |
Upper Case |
Lower Case |
Description |
| tr (Turkish) |
\u0130 |
\u0069 |
capital letter I with dot above -> small letter i |
| tr (Turkish) |
\u0049 |
\u0131 |
capital letter I -> small letter dotless i |
| (all) |
French Fries |
french fries |
lowercased all chars in String |
| (all) |


 |


 |
lowercased all chars in String |
toString
public String toString(
)
This object (which is already a string!) is itself returned.
toUpperCase
public String toUpperCase(
)
Converts all of the characters in this String to upper
case using the rules of the default locale. This method is equivalent to
toUpperCase(Locale.getDefault()).
toUpperCase
public String toUpperCase(
Locale locale
)
Converts all of the characters in this String to upper
case using the rules of the given Locale. Case mappings rely
heavily on the Unicode specification's character data. Since case mappings
are not always 1:1 char mappings, the resulting String may
be a different length than the original String.
Examples of locale-sensitive and 1:M case mappings are in the following table.
| Language Code of Locale |
Lower Case |
Upper Case |
Description |
| tr (Turkish) |
\u0069 |
\u0130 |
small letter i -> capital letter I with dot above |
| tr (Turkish) |
\u0131 |
\u0049 |
small letter dotless i -> capital letter I |
| (all) |
\u00df |
\u0053 \u0053 |
small letter sharp s -> two letters: SS |
| (all) |
Fahrvergnügen |
FAHRVERGNÜGEN |
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trim
public String trim(
)
Returns a copy of the string, with leading and trailing whitespace
omitted.
If this String object represents an empty character
sequence, or the first and last characters of character sequence
represented by this String object both have codes
greater than '\u0020' (the space character), then a
reference to this String object is returned.
Otherwise, if there is no character with a code greater than
'\u0020' in the string, then a new
String object representing an empty string is created
and returned.
Otherwise, let k be the index of the first character in the
string whose code is greater than '\u0020', and let
m be the index of the last character in the string whose code
is greater than '\u0020'. A new String
object is created, representing the substring of this string that
begins with the character at index k and ends with the
character at index m-that is, the result of
this.substring(k, m+1).
This method may be used to trim
whitespace from the beginning and end
of a string; in fact, it trims all ASCII control characters as well.
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